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(KMP 求循环节)The Minimum Length
阅读量:5291 次
发布时间:2019-06-14

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The Minimum Length
Time Limit:1000MS     Memory Limit:131072KB     64bit IO Format:%lld & %llu
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Description

There is a string A. The length of A is less than 1,000,000. I rewrite it again and again. Then I got a new string: AAAAAA...... Now I cut it from two different position and get a new string B. Then, give you the string B, can you tell me the length of the shortest possible string A. For example, A="abcdefg". I got abcd 
efgabcdefgabcdefgabcdefg.... Then I cut the red part: efgabcdefgabcde as string B. From B, you should find out the shortest A.

Input

Multiply Test Cases. For each line there is a string B which contains only lowercase and uppercase charactors. The length of B is no more than 1,000,000.

Output

For each line, output an integer, as described above.

Sample Input

bcabcabefgabcdefgabcde

Sample Output

37

 

#include
#include
#define N 1000007#define max(a,b) (a>b?a:b)int Next[N];char S[N];void FindNext(int Slen){ int i=0, j=-1; Next[0] = -1; while(i
0; i--) { if(i%(i-Next[i])==0) { printf("%d\n", i-Next[i]); break; } } } return 0;}
View Code

 

转载于:https://www.cnblogs.com/YY56/p/4835219.html

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